JEE Main & Advanced Physics Wave Mechanics Question Bank Vibration of String

  • question_answer
    Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is [CBSE PMT 1997; AIIMS 1998; JIPMER 2000]

    A)            2 Hz                                          

    B)            4 Hz

    C)            5 Hz                                          

    D)            10 Hz

    Correct Answer: C

    Solution :

                         String vibrates in five segment so \[\frac{5}{2}\lambda =l\]Þ \[\lambda =\frac{2l}{5}\]                    Hence \[n=\frac{v}{\lambda }=5\times \frac{v}{2l}\]\[=5\times \frac{20}{2\times 10}=5\]\[Hz\]


You need to login to perform this action.
You will be redirected in 3 sec spinner