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JEE Main & Advanced Physics Wave Mechanics Question Bank Vibration of String

  • question_answer
    A 1 cm long string vibrates with fundamental frequency of 256 Hz. If the length is reduced to \[\frac{1}{4}cm\] keeping the tension unaltered, the new fundamental frequency will be [BHU 1997]

    A)            64  

    B)            256

    C)            512

    D)            1024

    Correct Answer: D

    Solution :

                 \[n\propto \frac{1}{l}\]Þ \[\frac{{{n}_{2}}}{{{n}_{1}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\]Þ \[{{n}_{2}}=\frac{{{l}_{1}}}{{{l}_{2}}}{{n}_{1}}=\frac{1\times 256}{1/4}=1024Hz\]


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