A) \[C{{l}_{2}}\]
B) \[C{{l}^{-}}\]
C) \[B{{r}^{-}}\]
D) \[{{I}^{-}}\]
Correct Answer: D
Solution :
As it can donate \[{{e}^{-}}\] easily due to low comparative attraction by the nucleus to the valence \[{{e}^{-}}\].
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