• # question_answer 3 and 6 electrons are present in the outermost orbit of A and B respectively. The chemical formula of its compound will be A) ${{A}_{3}}{{B}_{2}}$ B) ${{A}_{2}}{{B}_{3}}$ C) ${{A}_{2}}B$ D) $AB$

${{A}_{2}}{{B}_{3}}$ $A\xrightarrow{-3{{e}^{-}}}{{A}^{+3}}$;  $B\xrightarrow{+2{{e}^{-}}}{{B}^{-2}}$