JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Units

  • question_answer
    SI unit of permittivity is [KCET 2004]

    A) \[{{C}^{2}}{{m}^{2}}{{N}^{-1}}\]

    B) \[{{C}^{-1}}{{m}^{2}}{{N}^{-2}}\]

    C) \[{{C}^{2}}{{m}^{2}}{{N}^{2}}\]

    D) \[{{C}^{2}}{{m}^{-2}}{{N}^{-1}}\]

    Correct Answer: D

    Solution :

    \[F=\frac{1}{4\pi \in }\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\Rightarrow \in =\frac{1}{4\pi }\frac{{{q}_{1}}{{q}_{2}}}{F{{r}^{2}}}={{C}^{2}}{{m}^{-2}}{{N}^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner