A) 115m
B) 60m
C) 165m
D) 135m
Correct Answer: A
Solution :
Let ABCD be the field which is in the form of an isosceles trapezium. AD = 50 m [Given] \[\therefore BC\text{ }=\text{ }50\text{ }m\] [Non-parallel sides of an isosceles trapezium are of equal length] Perimeter of trapezium ABCD \[=AB+BC+CD+DA\] \[\Rightarrow 215=(AB+CD)+50+50\] \[\Rightarrow 215=100+(AB+CD)\] \[\Rightarrow (AB+CD)=215-100=115m\] \[\therefore \] Sum of parallel sides \[=\text{ }115\text{ }m\]You need to login to perform this action.
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