A) \[2.8\times {{10}^{-3}}{{m}^{2}}{{s}^{-1}}\]
B) \[3.8\times {{10}^{-5}}{{m}^{2}}{{s}^{-1}}\]
C) \[5.8\times {{10}^{-5}}{{m}^{2}}{{s}^{-1}}\]
D) \[6.8\times {{10}^{-6}}{{m}^{2}}{{s}^{-1}}\]
Correct Answer: C
Solution :
Given that mass of electron \[=9.1\times {{10}^{-31}}kg\] Planck?s constant \[=6.63\times {{10}^{-34}}kg\,{{m}^{2}}{{s}^{-1}}\] By using \[\Delta x\times \Delta p=\frac{h}{4\pi }\]; \[\Delta x\times \Delta v\times m=\frac{h}{4\pi }\] where : \[\Delta x\]= uncertainity in position \[\Delta v\]= uncertainity in velocity \[\Delta x\times \Delta v=\frac{h}{4\pi \times m}\] \[=\frac{6.63\times {{10}^{-34}}}{4\times 3.14\times 9.1\times {{10}^{-31}}}\] \[=5.8\times {{10}^{-5}}{{m}^{2}}{{s}^{-1}}\].
You need to login to perform this action.
You will be redirected in
3 sec
