JEE Main & Advanced Chemistry Structure of Atom Question Bank Uncertainty principle and Schrodinger wave equation

  • question_answer The uncertainty in momentum of an electron is \[1\times {{10}^{-5}}kg-m/s\]. The uncertainty in its position will be (\[h=6.62\times {{10}^{-34}}kg-{{m}^{2}}/s\]) [AFMC 1998; CBSE PMT 1999; JIPMER 2002]

    A)                 \[1.05\times {{10}^{-28}}m\]     

    B)                 \[1.05\times {{10}^{-26}}m\]

    C)                 \[5.27\times {{10}^{-30}}m\]     

    D)                 \[5.25\times {{10}^{-28}}m\] 

    Correct Answer: C

    Solution :

               According to \[\Delta x\,\times \Delta p=\frac{h}{4\pi }\]                 \[\Delta x=\frac{h}{\Delta p\times 4\pi }=\frac{6.62\times {{10}^{-34}}}{1\times {{10}^{-5}}\times 4\times 3.14}\]\[=5.27\times {{10}^{-30}}m\].

You need to login to perform this action.
You will be redirected in 3 sec spinner