A) \[\left[ \begin{matrix} 1/2 & 2 \\ -1/2 & 1 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 1/2 & -1/2 \\ 2 & 1 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} 2 & 2 \\ 1/2 & -1/2 \\ \end{matrix} \right]\]
D) None of these
Correct Answer: B
Solution :
\[{{a}_{ij}}=\frac{1}{2}(3i-2j)\] Þ \[{{a}_{11}}=1/2,\,\,\,{{a}_{12}}=-1/2\] and \[{{a}_{21}}=2,\,\,\,{{a}_{22}}=1\] \[\therefore \] \[A={{[{{a}_{ij}}]}_{2\times 2}}=\left[ \begin{matrix} {{a}_{\text{11}}} & {{a}_{12}} \\ {{a}_{\text{21}}} & {{a}_{22}} \\ \end{matrix} \right]\] \[\therefore \] \[A=\left[ \begin{matrix} 1/2 & -1/2 \\ 2 & 1 \\ \end{matrix} \right]\].
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