A) \[\left[ \begin{matrix} 8 & 20 \\ 7 & 9 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 8 & -20 \\ 7 & -9 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} -8 & 20 \\ -7 & 9 \\ \end{matrix} \right]\]
D) \[\left[ \begin{matrix} 8 & 7 \\ -20 & -9 \\ \end{matrix} \right]\]
Correct Answer: B
Solution :
\[5A-3B+2C=\left[ \begin{matrix} 5 & -10 \\ 15 & 0 \\ \end{matrix} \right]-\left[ \begin{matrix} -3 & 12 \\ 6 & 9 \\ \end{matrix} \right]-\left[ \begin{matrix} 0 & -2 \\ 2 & 0 \\ \end{matrix} \right]\] \[=\left[ \begin{matrix} 5 & -10 \\ 15 & 0 \\ \end{matrix} \right]-\left[ \begin{matrix} -3 & 10 \\ 8 & 9 \\ \end{matrix} \right]=\left[ \begin{matrix} 8 & -20 \\ 7 & -9 \\ \end{matrix} \right]\].
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