JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Types of matrices, Algebra of matrices

  • question_answer
    If \[M=\left[ \begin{matrix}    1 & 2  \\    2 & 3  \\ \end{matrix} \right]\]and \[{{M}^{2}}-\lambda M-{{I}_{2}}=0\], then \[\lambda =\] [MP PET 1990, 2001]

    A) - 2

    B) 2

    C) - 4

    D) 4

    Correct Answer: D

    Solution :

    \[{{M}^{2}}-\lambda M-{{I}_{2}}=0\] \[\Rightarrow \,\,\left[ \begin{matrix}    1 & 2  \\    2 & 3  \\ \end{matrix} \right]\left[ \begin{matrix}    1 & 2  \\    2 & 3  \\ \end{matrix} \right]-\left[ \begin{matrix}    \lambda  & 2\lambda   \\    2\lambda  & 3\lambda   \\ \end{matrix} \right]-\left[ \begin{matrix}    1 & 0  \\    0 & 1  \\ \end{matrix} \right]=O\] \[\Rightarrow \,\,\left[ \begin{matrix}    5 & 8  \\    8 & 13  \\ \end{matrix} \right]-\left[ \begin{matrix}    \lambda  & 2\lambda   \\    2\lambda  & 3\lambda   \\ \end{matrix} \right]-\left[ \begin{matrix}    1 & 0  \\    0 & 1  \\ \end{matrix} \right]=O\] \[\Rightarrow \,\,\left[ \begin{matrix}    5-\lambda  & 8-2\lambda   \\    8-2\lambda  & 13-3\lambda   \\ \end{matrix} \right]=\left[ \begin{matrix}    1 & 0  \\    0 & 1  \\ \end{matrix} \right]\] Þ \[5-\lambda =1,\,\,8-2\lambda =0,\,\,13-3\lambda =1\] Þ \[\lambda =4\], which satisfies all the three equations.


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