A) \[\frac{10}{\sqrt{3}}\]m
B) \[10\sqrt{3}\]m
C) \[\frac{20}{\sqrt{3}}\]m
D) 30 m
Correct Answer: D
Solution :
(d): \[tan{{30}^{{}^\circ }}=\frac{10}{PQ}\] \[\frac{1}{\sqrt{3}}=\frac{10}{PQ},PQ=10\sqrt{3}\] \[\tan {{60}^{{}^\circ }}=\frac{SQ}{10\sqrt{3}}=\frac{SR+10}{10\sqrt{3}}\] \[\sqrt{3}=\frac{SR+10}{10\sqrt{3}}\] \[SR=20\] \[SQ=20+10=30\]
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