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10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    In the given figure \[\sin \theta =\]?

    A) \[\frac{m+n}{m-n}\]

    B) \[\frac{m}{m+n}\]

    C) \[\frac{m-n}{m+n}\]

    D) \[\frac{n}{m+n}\]

    Correct Answer: C

    Solution :

    (c): \[AB=\sqrt{{{\left( \frac{m+n}{2\sqrt{mn}} \right)}^{2}}-1}\] \[=\frac{m-n}{2\sqrt{mn}}\] \[\sin \theta =\frac{\frac{m-n}{2\sqrt{mn}}}{\frac{m+n}{2\sqrt{mn}}}\] \[=\frac{m-n}{m+n}\]


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