A) \[\frac{3}{5}\]
B) \[\frac{2}{5}\]
C) \[-\frac{3}{5}\]
D) \[-\frac{2}{5}\]
Correct Answer: A
Solution :
(a): \[\sec \theta +\tan \theta =2\] \[\therefore \] \[\sec \theta -\tan \theta =\frac{1}{2}\] \[\{since(sec\theta +tan\theta )(sec\theta -tan\theta )=1\}\] Solving, we get, \[\sec \theta =\frac{5}{4}\] and \[\tan \theta =\frac{3}{4}\] \[\therefore \] \[\sin \theta =\frac{\tan \theta }{\sec \theta }=\frac{3}{5}\]
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