A) \[2{{\sec }^{2}}\theta \]
B) \[2co{{s}^{2}}\theta \]
C) \[0\]
D) \[1\]
Correct Answer: A
Solution :
(a) \[\frac{1-\sin \theta +1+\sin \theta }{1-{{\sin }^{2}}\theta }\] \[=\frac{2}{{{\cos }^{2}}\theta }=2{{\sec }^{2}}\theta \]
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