A) \[\frac{200}{3}\]
B) \[200\sqrt{3}\]
C) \[\frac{400}{3}\]
D) \[400\sqrt{3}\]
Correct Answer: C
Solution :
(c): \[\angle BCA={{60}^{{}^\circ }}\] \[tan{{60}^{{}^\circ }}=\frac{200}{BC}\] \[\sqrt{3}=\frac{200}{BC},BC=\frac{200}{\sqrt{3}}\] \[ED=BC=\frac{200}{\sqrt{3}}\] \[tan{{30}^{{}^\circ }}=\frac{AE}{ED}\] \[\frac{1}{\sqrt{3}}=\frac{AE}{\frac{200}{\sqrt{3}}}\] \[\therefore AE=\frac{200}{3}\] \[EB=200-\frac{200}{3}=\frac{400}{3}\] \[\therefore CD=\frac{400}{3}\]
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