A) 25
B) 50
C) 75
D) 80
Correct Answer: B
Solution :
Since \[AB=BP\] \[\therefore \] \[\angle BAP=\angle BPA={{15}^{o}}\] Consequently, \[\angle PBQ={{30}^{o}}\] \[PQ=100\,\sin {{30}^{o}}\] \[=50\,cm\]
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