A) \[\text{sinA}-\text{cosA}\]
B) sin A + cos A
C) \[\text{1 }-\text{ cos A}\]
D) \[\text{1}-\text{ sin A}\]
Correct Answer: B
Solution :
\[\frac{\cos \,A}{1-\tan A}+\frac{\sin A}{1-\cot A}\] \[=\frac{{{\cos }^{2}}A}{\cos A-\sin A}+\frac{{{\sin }^{2}}A}{\sin A-\cos A}\] \[=\frac{{{\cos }^{2}}A-{{\sin }^{2}}A}{\cos A-\sin A}\] \[=\cos A+\sin A\]
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