A) \[(1-k)\]
B) \[(1+k)\]
C) \[\frac{1}{k}\]
D) \[1-\frac{1}{k}\]
Correct Answer: C
Solution :
Given, \[\sec \theta -\tan \theta =k\] ..?..(i) Also, \[{{\sec }^{2}}\theta -{{\tan }^{2}}\theta =1\] ??.(ii) Dividing equation (u) by d), we get \[\frac{{{\sec }^{2}}\theta -{{\tan }^{2}}\theta }{\sec \theta -\tan \theta }=\frac{1}{k}\] or \[\sec \theta +\tan \theta =\frac{1}{k}\]
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