A) 0
B) 1/2
C) 1
D) \[4\cos \alpha \cos \beta \cos \gamma \]
Correct Answer: A
Solution :
\[\cos \alpha \sin (\beta -\gamma )+\cos \alpha \sin (\gamma -\alpha )+\cos \gamma \sin (\alpha -\beta )\] Put\[\alpha =\beta =\gamma ={{60}^{o}}\Rightarrow \frac{1}{2}(0)+\frac{1}{2}(0)+\frac{1}{2}(0)=0\].
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