JEE Main & Advanced Mathematics Trigonometric Identities Question Bank Trigonometrical ratios of sum and difference of two and three angles

  • question_answer
    The value of \[\cos 15{}^\circ -\sin 15{}^\circ \]is equal to [MNR 1975; MP PET 1994, 2002]

    A) \[\frac{1}{\sqrt{2}}\]

    B) \[\frac{1}{2}\]

    C) \[-\frac{1}{\sqrt{2}}\]

    D) 0

    Correct Answer: A

    Solution :

    \[\cos {{15}^{o}}-\sin {{15}^{o}}=\sqrt{2}\,.\cos \,({{45}^{o}}+{{15}^{o}})=\sqrt{2}\,.\,\cos \,\,{{60}^{o}}\] \[=\sqrt{2}\,.\frac{1}{2}=\frac{1}{\sqrt{2}}\].


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