JEE Main & Advanced Mathematics Trigonometric Identities Question Bank Trigonometrical ratios of sum and difference of two and three angles

  • question_answer
    The value of \[\sin {{47}^{o}}+\sin 61{}^\circ -\sin 11{}^\circ -\sin 25{}^\circ =\] [MP PET 2001; EAMCET 2003]

    A) \[\sin 36{}^\circ \]

    B) \[\cos 36{}^\circ \]

    C) \[\sin 7{}^\circ \]

    D) \[\cos 7{}^\circ \]

    Correct Answer: D

    Solution :

    \[\sin \,\,{{47}^{o}}+\sin \,\,{{61}^{o}}-(\sin \,\,{{11}^{o}}+\sin \,\,{{25}^{o}})\] \[=\frac{\sin \,\,{{20}^{o}}\sin \,\,{{40}^{o}}\sin \,\,{{80}^{o}}}{\cos \,\,{{20}^{o}}\cos \,\,{{40}^{o}}\cos \,\,{{80}^{o}}}\] \[=\,\,2\,\,\cos \,\,{{7}^{o}}\,(\sin \,\,{{54}^{o}}-\sin \,\,{{18}^{o}})\] \[=\,\,2\,\,\cos \,\,{{7}^{o}}\,\,.\,\,2\,\,\cos \,\,{{36}^{o}}\,\,.\,\,\sin \,\,{{18}^{o}}\] \[=\,\,4.\,\cos \,\,{{7}^{o}}.\,\frac{\sqrt{5}+1}{4}.\frac{\sqrt{5}-1}{4}=\cos \,\,{{7}^{o.}}\].


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