JEE Main & Advanced Mathematics Trigonometric Identities Question Bank Trigonometrical ratios of multiple and sub multiple angles

  • question_answer
    \[\frac{\sqrt{1+\sin x}+\sqrt{1-\sin x}}{\sqrt{1+\sin x}-\sqrt{1-\sin x}}=\] (when x lies in IInd quadrant)

    A) \[\sin \frac{x}{2}\]

    B) \[\tan \frac{x}{2}\]

    C) \[\sec \frac{x}{2}\]

    D) \[\text{cosec}\frac{x}{2}\]

    Correct Answer: B

    Solution :

    \[\frac{\sqrt{1+\sin x}+\sqrt{1-\sin x}}{\sqrt{1+\sin x}-\sqrt{1-\sin x}}=\frac{\cos \frac{x}{2}+\sin \frac{x}{2}+\sin \frac{x}{2}-\cos \frac{x}{2}}{\cos \frac{x}{2}+\sin \frac{x}{2}-\sin \frac{x}{2}+\cos \frac{x}{2}}\] \[=\tan \frac{x}{2}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner