A) \[\frac{9}{2}\]
B) \[\frac{11}{2}\]
C) \[\frac{7}{2}\]
D) \[-\frac{1}{2}\]
Correct Answer: B
Solution :
We have \[\tan A=\frac{1}{2}\] \[\Rightarrow \tan 3A=\frac{3\tan A-{{\tan }^{3}}A}{1-{{\tan }^{2}}A}=\frac{3.\frac{1}{2}-\frac{1}{8}}{1-3.\frac{1}{4}}=\frac{12-1}{2}=\frac{11}{2}\].
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