A) \[2\sin A\]
B) \[\sec A\]
C) \[2\cos A\cot A\]
D) None of these
Correct Answer: A
Solution :
\[\text{cosec}\,A-2\cot 2A\cos A=\frac{1}{\sin A}-\frac{2\cos A\cos 2A}{\sin 2A}\] \[=\frac{1}{\sin A}-\frac{2\cos A\cos 2A}{2\sin A\cos A}=\frac{1-\cos 2A}{\sin A}=\frac{2{{\sin }^{2}}A}{\sin A}\] \[=2\sin A\].
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