A) \[-5\]
B) \[5\]
C) \[9/4\]
D) \[4/9\]
Correct Answer: D
Solution :
Given that\[\tan \frac{A}{2}=\frac{3}{2}\]. \[\frac{1+\cos A}{1-\cos A}=\frac{2{{\cos }^{2}}\frac{A}{2}}{2{{\sin }^{2}}\frac{A}{2}}={{\cot }^{2}}\frac{A}{2}={{\left( \frac{2}{3} \right)}^{2}}=\frac{4}{9}\].
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