A) 1.5
B) 3.2
C) 1
D) 5
Correct Answer: C
Solution :
(c): \[\frac{PS}{SQ}=\frac{PT}{TR}\Rightarrow \frac{x+2}{x+3}=\frac{2x+1}{4x}\] \[\Rightarrow \]\[4{{x}^{2}}+8x=2{{x}^{2}}+7x+3\] \[\Rightarrow \]\[2{{x}^{2}}+x-3=0\Rightarrow x=\frac{-1\pm \sqrt{25}}{4}\] \[=\frac{-1+5}{4}=\frac{-3}{2},1\] (in the given options, x = 1 matches)
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