A) \[3C{{A}^{2}}\]
B) \[4B{{D}^{2}}\]
C) \[3C{{D}^{2}}\]
D) \[C{{A}^{2}}\]
Correct Answer: C
Solution :
(c): Let \[AB=BC=AC=a\] \[BD=DC=\frac{a}{2}\] \[\Rightarrow \] \[A{{D}^{2}}=\left( {{a}^{2}}-{{\left( \frac{a}{2} \right)}^{2}} \right)\] \[\Rightarrow \] \[A{{D}^{2}}=\frac{3}{4}{{a}^{2}}\] \[\Rightarrow \]\[A{{D}^{2}}=3{{\left( \frac{a}{2} \right)}^{2}}=3.C{{D}^{2}}\]
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