question_answer

In \[ABC,\angle A={{85}^{o}},\angle B={{30}^{o}}\]and \[\angle C={{65}^{o}}\]then

A)  AB > AC                    

B)         AB < AC        

C)         BC < AC                    

D)         None of these   

Correct Answer: A

Solution :

In any triangle the side opposite to the greater angle is longer. Since, \[\angle C>\angle B\] \[\Rightarrow \]\[AB>AC\]and \[\angle B=\angle A\Rightarrow AC<BC\]