A) Isosceles but not necessarily congruent
B) Isosceles and congruent
C) Congruent but not isosceles
D) Neither congruent nor isosceles
Correct Answer: A
Solution :
In \[\Delta DEF,\,DE=DF.\]So,\[\Delta DEF\]is isosceles. \[\therefore \]\[\angle F=\angle E\] ?(i) Also, \[\angle F=\angle P\]and \[\angle E=\angle Q\] ?(ii) From (i) and (ii), we get \[\angle P=\angle Q\] Now, in \[\Delta PQR,\angle P=\angle Q\Rightarrow RQ=PR\] So, \[\Delta PQR\]is isosceles. Hence, \[\Delta DEF\]and \[\Delta PQR\]are isosceles but not necessarily congruent.You need to login to perform this action.
You will be redirected in
3 sec