A) \[{{106}^{o}}\]
B) \[{{53}^{o}}\]
C) \[{{26}^{o}}\]
D) \[{{52}^{o}}\]
Correct Answer: C
Solution :
In \[\Delta ABC,\] \[\angle ACB=\angle {{180}^{o}}-\] \[({{35}^{o}}+{{39}^{o}})={{180}^{o}}-{{74}^{o}}={{106}^{o}}\] AE and BD intersect at C \[\Rightarrow \] \[\angle DCE=\angle ACB={{106}^{o}}\] (Vertically opposite angles) \[\Rightarrow \] \[x={{180}^{o}}-({{106}^{o}}+{{48}^{o}})={{26}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
