JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Topic Test - Thermometry, Calorimetry & Thermal Expansion

The freezing point on a thermometer is marked as -\[{{20}^{\circ }}\]and the boiling point as \[{{130}^{\circ }}\]. A temperature of human body \[({{34}^{\circ }}C)\]on this thermometer will be read as:

A) \[{{31}^{\circ }}\]

B) \[{{51}^{\circ }}\]

C) \[{{20}^{\circ }}\]

D) none of these

Correct Answer: A

Solution :

\[{{100}^{\circ }}C={{150}^{\circ }}\] of the thermometer

\[\therefore \]\[{{1}^{\circ }}C={{1.5}^{\circ }}\] of the thermometer

Or \[{{34}^{\circ }}C={{51}^{\circ }}\] of the thermometer

\[\therefore \] thermometer will read \[-{{20}^{\circ }}+{{51}^{\circ }}={{31}^{\circ }}\]of the thermometer