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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Topic Test - Electrochemistry

  • question_answer
    A current of 2.0 A when passed for 5 hours through a molten metal salt deposits 22.2 g of metal of atomic weight 177. The oxidation state of the metal in the metal salt is

    A) + 1

    B) + 2

    C) + 3

    D) + 4

    Correct Answer: C

    Solution :

    [c] \[{{E}_{metal}}=\] (Wt of metal \[\times \] 96500)/No of coulombs  \[=\frac{(22.2\times 96500)}{(2\times 5\times 60\times 60)}=59.5\]
    Oxidation no. of metal \[=\frac{177}{59.5}=+3\]


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