A) +1.820 V
B) +1.990 V
C) +1.608 V
D) +1.0542 V
Correct Answer: D
Solution :
| [d] \[{{E}_{C{{r}_{2}}O_{7}^{2-}{{\left| Cr \right.}^{3+}}}}=E{{{}^\circ }_{C{{r}_{2}}O_{7}^{2-}{{\left| Cr \right.}^{3+}}}}\,-\frac{0.0591}{6}\]\[\times \left( \log \frac{{{[C{{r}^{3+}}]}^{2}}}{[C{{r}_{2}}O_{7}^{2-}]}\times \frac{1}{{{[{{H}^{+}}]}^{14}}} \right)\] |
| \[{{E}_{C{{r}_{2}}O_{7}^{2-}{{\left| Cr \right.}^{3+}}}}=1.33-\frac{0.0591}{6}\log \frac{1}{{{(0.01)}^{14}}}\] |
| \[\Rightarrow \] \[1.0542\,V\] |
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