JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Topic Test - Electrochemistry

  • question_answer
    Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 S/m. Resistance of the same cell filled with 0.02 M of the same solution if the electrolyte is 520 ohm. The molar conductivity of 0.02 M solution of electrolyte would be:

    A) \[124\times {{10}^{-4}}S-{{m}^{2}}/mol\]

    B) \[1240\times {{10}^{-4}}S-{{m}^{2}}/mol\]

    C) \[1.24\times {{10}^{-4}}S-{{m}^{2}}/mol\]

    D) \[12.4\times {{10}^{-4}}S-{{m}^{2}}/mol\]

    Correct Answer: A

    Solution :

    [a] at \[c=0.1\,M;\]
    \[\frac{l}{a}=kR=1.29\times 100\] at \[c=0.02\text{ }M;\]
    \[\kappa =\frac{\ell }{a\times R}=\frac{1.29\times 100}{520}=0.248\,S/m\]
    Also, \[\Lambda =\frac{k}{M\left( in\,mol/l \right)}=\frac{k}{M\times {{10}^{3}}\left( in\,mol/{{m}^{3}} \right)}\]
    \[=\frac{0.248}{0.02\times {{10}^{3}}}=124\times {{10}^{-4}}S{{m}^{2}}/mol\]


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