JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Topic Test - Electrochemistry

  • question_answer
    3F of electricity passes through three electrolytic cells connected in series containing  \[A{{g}^{+}},C{{a}^{2+}}\] and \[A{{l}^{3+}}\] ions, respectively. The molar ratio in which the three metal ions are liberated at the electrodes is

    A) 1 : 2 : 3

    B) 2 : 3 : 1 

    C) 6 : 3 : 2

    D) 3 : 4 : 2

    Correct Answer: C

    Solution :

    [c] 1 Eq of \[A{{g}^{+}}:1\] Eq of \[C{{a}^{2+}}:1\] Eq of \[A{{l}^{3+}}\]
    1 mol of \[A{{g}^{2+}};\frac{1}{2}\] mol of \[C{{a}^{2+}};\frac{1}{3}\] mol of \[A{{l}^{3+}}\]
    \[\therefore \] mole ratio is \[1:\frac{1}{2}:\frac{1}{3}=6:3:2\]


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