• # question_answer Starting from his house, one day a student walks at a speed of $2\frac{1}{2}$ km/hr and reaches his school 6 minutes late. Next day he increases his speed by 1 km/hr and reaches the school 6 minutes early. How far is the school from his house? A)  1.5 kmB)  1.75 kmC)  2.25 km           D)  2.5 km

[b] Distance from his house $\text{=}\frac{\text{Product}\,\,\text{of}\,\,\text{speed}}{\text{Difference}\,\,\text{of}\,\,\text{speed}}\,\,\text{ }\!\!\times\!\!\text{ }\,\,\text{total}\,\,\text{time}$ $=\frac{\frac{5}{2}\times \frac{7}{2}}{1}\times \frac{12}{60}$ $=\frac{35}{4}\times \frac{1}{5}=\frac{7}{4}=1.75\,km$