A) \[2\pi \sqrt{b}\]
B) \[\frac{2\pi }{\sqrt{b}}\]
C) \[\frac{2\pi }{b}\]
D) \[2\sqrt{\frac{\pi }{b}}\]
Correct Answer: B
Solution :
In the given case, \[\frac{Displacement}{Acceleration}=\frac{1}{b}\] \ Time period \[T=2\pi \sqrt{\frac{Displacement}{Acceleration}}=\frac{2\pi }{\sqrt{b}}\]
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