question_answer

Heat equivalent to 50 joule is supplied to a thermodynamic system and 10 joule work is done on the system. What is the change in the internal energy of the system in the process?

Answer:

                 Here \[\Delta Q=+50J,\Delta W=-10J\] \[\therefore \]   \[\Delta U=\Delta Q-\Delta W=50-(-10)=+\mathbf{60J}\] Thus internal energy of the system increases by \[\mathbf{60J}\].