Statement 1: The sum of the lengths of any two sides of a triangle is greater than the length of the third side. |
Statement 2: If P is a point on the side BC of \[\Delta ABC\]. Then \[(AB+BC+AC)>2AP\] |
A) Only Statement-1
B) Only Statement-2
C) Both Statement-1 and Statement-2
D) Neither Statement-1 nor Statement-2
Correct Answer: C
Solution :
Statement - 2 In \[\Delta ABP,~\] \[AB+BP>AP~\] ?..(i) In \[\Delta APC\] \[PC+AC>AP\] ?..(ii) Adding (i) & (ii), we get \[AB+BP+PC+AC>AP+AP\] \[\Rightarrow \] \[AB+BC+AC>2AP\] \[\therefore \] Both Statement -1 and Statement-2 are true.You need to login to perform this action.
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