A) \[12\times {{10}^{23}}\]
B) \[26\times {{10}^{23}}\]
C) \[34\times {{10}^{23}}\]
D) \[48\times {{10}^{23}}\]
Correct Answer: D
Solution :
As we know that four sodium atom are present in sodium ferrocyanide \[[N{{a}_{4}}Fe{{(CN)}_{6}}]\] Hence, number of \[Na\] atoms = No. of moles \[\times \] number of atom \[\times \] Avogadro?s number \[2\times 4\times 6.023\times {{10}^{23}}=48\times {{10}^{23}}\]
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