A) 0.1
B) 0.2
C) 0.3
D) 0.4
Correct Answer: A
Solution :
Molecular weight of \[S{{O}_{2}}C{{l}_{2}}\] \[=32+32+2\times 35.5\]= 135gm \[\because \] 135 gm of \[S{{O}_{2}}C{{l}_{2}}\] = 1gm molecule \[\therefore \] 13.5gm of \[S{{O}_{2}}C{{l}_{2}}\] \[=\frac{1}{135}\times 13.5=0.1\].You need to login to perform this action.
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