A) -1
B) 1
C) 0
D) No real values
Correct Answer: A
Solution :
\[\left| \,\begin{matrix} 1 & a & 0 \\ 0 & 1 & a \\ a & 0 & 1 \\ \end{matrix}\,\, \right|=0\Rightarrow 1+a({{a}^{2}})=0\Rightarrow {{a}^{3}}=-1\Rightarrow a=-1.\]
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