JEE Main & Advanced Mathematics Determinants & Matrices Question Bank System of linear equations, Some special determinants, differentiation and integration of determinants

  • question_answer
    If \[\left| \,\begin{matrix}    1+ax & 1+bx & 1+cx  \\    1+{{a}_{1}}x & 1+{{b}_{1}}x & 1+{{c}_{1}}x  \\    1+{{a}_{2}}x & 1+{{b}_{2}}x & 1+{{c}_{2}}x  \\ \end{matrix}\, \right|,\] \[={{A}_{0}}+{{A}_{1}}x+{{A}_{2}}{{x}^{2}}+{{A}_{3}}{{x}^{3}}\]  then \[{{A}_{1}}\] is equal to [AMU 2002]

    A) abc

    B) 0

    C) 1

    D) None of these

    Correct Answer: B

    Solution :

    \[(1+ax)\,[(1+{{b}_{1}}x)\,(1+{{c}_{2}}x)-(1+{{b}_{2}}x)\,(1+{{c}_{1}}x)]\]+ \[(1+bx)[(1+{{c}_{1}}x)(1+{{a}_{2}}x)-(1+{{a}_{1}}x)\,(1+{{c}_{2}}x)]\]  + \[(1+cx)\,[(1+{{a}_{1}}x)\,(1+{{b}_{2}}x)-(1+{{b}_{1}}x)\,(1+{{a}_{2}}x)]\]= \[{{A}_{0}}+{{A}_{1}}x+{{A}_{2}}{{x}^{2}}+{{A}_{3}}{{x}^{3}}\] After solving, the coefficient of x is 0.


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