A) 1
B) 2
C) 0
D) None of these
Correct Answer: C
Solution :
If r is the common ratio, then \[{{a}_{n}}={{a}_{1}}{{r}^{n-1}}\]for all \[n\ge 1\Rightarrow \log {{a}_{n}}=\log {{a}_{1}}+(n-1)\log r\] = \[A+(n-1)R\], where \[\log {{a}_{1}}=A\]and \[\log r=R\]. Thus in\[\Delta \], on applying \[{{C}_{2}}\to {{C}_{2}}-{{C}_{1}}\] and \[{{C}_{3}}\to {{C}_{3}}-{{C}_{2}}\], we obtain \[{{C}_{2}}\]and \[{{C}_{3}}\]are identical. Thus\[\Delta =0\].You need to login to perform this action.
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