A) 1
B) -1
C) \[\sqrt{3}\]
D) \[-\sqrt{3}\]
Correct Answer: C
Solution :
\[{{l}^{2}}={{2}^{2}}+{{2}^{2}}=8={{(\sqrt{3}+1)}^{2}}+{{(k-1)}^{2}}\,\,\Rightarrow \,\,k=\sqrt{3}\].
You need to login to perform this action.
You will be redirected in
3 sec
