A) \[92.5\,c{{m}^{3}}\]
B) \[72\,c{{m}^{3}}\]
C) \[63.5\text{ }c{{m}^{3}}\]
D) \[81\text{ }c{{m}^{3}}\]
Correct Answer: D
Solution :
Outer dimensions of the box are 10 cm, 9 cm and 2.5 cm. Thickness of the box is \[0.5\text{ }cm.\] So, inner dimensions of the box is \[(10-2\times 0.5)cm,\] \[(9-2\times 0.5)cm,\] and \[(2.5-0.5)cm\] i.e, 9 cm, 8 cm and 2 cm Volume of the metal = Volume of outer box - Volume of inner box \[=10\times 9\times 2.5-9\times 8\times 2=225-144=81c{{m}^{3}}\]
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