A) \[150\,\,c{{m}^{2}}\]
B) \[160.86\,c{{m}^{2}}\]
C) \[162.86\,c{{m}^{2}}\]
D) \[163.86\,c{{m}^{2}}\]
Correct Answer: D
Solution :
Total surface area of the block = Total surface area of cube + Curved surface area of hemisphere - Area of base of hemisphere \[=6\times {{(5)}^{2}}+2\pi \times {{(2.1)}^{2}}-\pi \times {{(2.1)}^{2}}\] \[=150+\pi \times {{(2.1)}^{2}}-\pi \times {{(2.1)}^{2}}=150+13.86=163.86c{{m}^{2}}\]
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