10th Class Mathematics Surface Areas and Volumes Question Bank Surface Area and Volume (Mensuration)

  • question_answer In a swimming pool measuring 90 m by 40 m, 150 men take a dip. If the average displacement of water by a man is 8 cubic metres, what will be the rise in the water level?

    A)  30 cm                         

    B)  50 cm        

    C)  20 cm             

    D)  33.33 cm

    Correct Answer: D

    Solution :

    (d): Let the rise in height be = h Then, as per the question, the volume of water should be equal in both the cases. Now, \[90\times 40\times h=150\times 8\] \[\therefore \]      \[h=\frac{150\times 8}{90\times 40}=\frac{1}{3}m=\frac{100}{3}cm=33.33\,\,cm\]


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