• # question_answer In a swimming pool measuring 90 m by 40 m, 150 men take a dip. If the average displacement of water by a man is 8 cubic metres, what will be the rise in the water level? A)  30 cm                         B)  50 cm        C)  20 cm             D)  33.33 cm

(d): Let the rise in height be = h Then, as per the question, the volume of water should be equal in both the cases. Now, $90\times 40\times h=150\times 8$ $\therefore$      $h=\frac{150\times 8}{90\times 40}=\frac{1}{3}m=\frac{100}{3}cm=33.33\,\,cm$