A) 10665 mm
B) 42660 mm
C) 21333 mm
D) 14220 mm
Correct Answer: C
Solution :
(c): The volume in both the cases would be the same. Therefore \[\frac{4\pi {{R}^{3}}}{3}=\pi {{r}^{2}}h\] \[\therefore \] \[\frac{4\times 3.14\times {{(4\times 10)}^{3}}}{3}=3.14\times {{2}^{2}}\times h\] \[\Rightarrow \] \[h=\frac{64000}{3}=21333.33\,mm\] (Note that R and r are different, R = radius of sphere = 4cm = 40mm, r = radius of wire\[\frac{4\,mm}{2}=2\,mm\]. Its better to immediately draw rough diagrams.)
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